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A charge is placed at the centre of the line joining two charges q and q. For the system of three charges to be in equilibrium, what should be the value of Q? |
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Answer» Solution :Here Q is in equilibrium as it is at the centre and NET FORCE on it is ZERO For equilibrium of q, net force on it is zero `1/(4 pi epsilon_0) (Qq)/((r//2)^2) + 1/(4 pi epsilon_0) (q^2)/(r^2) = 0` where r is separation between q and q `IMPLIES Q = (-q)/(4)` . |
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