1.

A charge of 1muC is divided into two parts such that their charges are in the ratio of 2:3. These two charges are kept at a distance 1m apart is vacuum. Then, the electric force between them (in N) is

Answer»

`0.216`
`0.00216`
`0.0216`
`2.16`

SOLUTION :(b) Ratio of charges `=2:3`
`:. q_(1)=2/5xx5xx1 mu C` and `q_(2)=35xx1 muC`
Electrostatic force between the two charges
`F=1/(4pi epsilon_(0))(q_(1)q_(2))/(r^(2))`
`=(9xx10^(9)xx2xx10^(-6)xx3xx10^(-6))/(5xx5xx(1)^(2))`
`=2.16xx10^(-3)N`
`~~0.00216N`


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