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A charge of `1muC` is divided into two parts such that their charges are in the ratio of `2:3`. These two charges are kept at a distance `1m` apart is vacuum. Then, the electric force between them (in `N`) isA. `0.216`B. `0.00216`C. `0.0216`D. `2.16` |
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Answer» (b) Ratio of charges `=2:3` `:. q_(1)=2/5xx5xx1 mu C` and `q_(2)=35xx1 muC` Electrostatic force between the two charges `F=1/(4pi epsilon_(0))(q_(1)q_(2))/(r^(2))` `=(9xx10^(9)xx2xx10^(-6)xx3xx10^(-6))/(5xx5xx(1)^(2))` `=2.16xx10^(-3)N` `~~0.00216N` |
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