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A charge of 8mC is located at the origin. Calculate the work done in taking a small charge of -2 xx 10^(-9)C from a point P (0,0,3 cm) to a point Q(0,4cm,0), via a point F (0.6 cm, 9cm). |
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Answer» SOLUTION :q=8mC `=8 xx 10^(-3)C q_(0)=-2 xx 10^(-9)C` Work DONE =change in PE `U_(1)=(1)/(4pi epsi_(0)) (q_(1)q_(2))/(r_(1)r_(2))=(9 xx 10^(9) xx 8 xx 10^(-3) xx (-2) xx 10^(-9))/(3 xx 10^(-2))` `U_(2)=(9 xx 10^(9) xx 8 xx 10^(-3) xx -2 xx 10^(-9))/(4 xx 10^(-2))` `U_(2)-U_(1)=(9 xx 10^(9) xx 8 xx 10^(-3) xx 2 xx 10^(-9))/(10^(-2)) {1/3-1/4}=9 xx 8 xx 2XX 10^(-1) xx 1/(12)=1.2J` |
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