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| 1. |
A charge of IC is placed at one end of a non conducting rod of length 0.6m . The rod is rotated in a vertical plane about a horizontal axis passing through the other end of the rod with angular frequency 10^(4)pi"rad"/s. Find the magnetic field at a point on the axis of rotation at a distance of 0.8 m from the centre of the path |
| Answer» SOLUTION :`B=(mu_(0)ir^(2))/(2(r^(2)+X^(2))^(3//2)),i=(qomega)/(2pi)rArrB=(mu_(0))/(4pi)(qomegar^(2))/((r^(2)+x^(2))^(3//2))` | |