1.

A charge oil drop is moving with a velcoity v_(1) As it acquire charge it moves up with the velcity V_(2) in the same electric field . It fall freely with a velocity 'V' in the absence before and after acquiring additional charge is

Answer»

`(V_(1)+V)/(V_(2)-V_(1))`
`(V_(1)+V_(2))/2V`
`(V+V_(1))/(V+V_(2))`
`(V_(2)V_2V_(1))/(2V_(1)+V)`

Solution :`Eq_(1)-mg=6pinaV_(1) to 1mg=6pinaV`
`Eq_(2)-mg=6pinaV_(2)TO2`


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