A charge particle after being accelerated through a potential difference V enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become

A charge particle after being accelerated through a potential differen

1.	A charge particle after being accelerated through a potential difference V enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become
Answer» 2r `sqrt(2r)` 4 R `(r )/(sqrt(2))` Solution :As per RELATION r=`r= (MV)/(qB)=(p)/(qB)=(sqrt(2mK))/(qB)=sqrt((2mV)/(qB^(2))),r prop sqrt(V)`

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A charge particle after being accelerated through a potential difference V enters in a uniform magnetic field and moves in a circle of radius r. If V is doubled, the radius of the circle will become

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