1.

A charge praticle of charge q is kept at the centre of the semicircular charged, ring . If linearcharge density is lambda every where, as shown in the figure. Then net electrostatic force on the particle is -

Answer»

`(lambdaq)/(4piepsi_(0)R)`
` (sqrt(5)lambdaq)/(4piepsi_(0)R)`
` (3lambdaq)/(4piepsi_(0)R)`
`(sqrt(2)lambdaq)/(4piespi_(0)R)`

Solution :Due to rod only
`vecF_(1)=(lambdaq)/(4piepsi_(0)R)`
Due to SEMICIRCLE only
`vecF_(2)=(lambdaq)/(2piepsi_(0)R)`
`F_("NET")sqrt(F_(1)^(2)+F_(2)^(2))rArrF_("net")=sqrt(5lambda_(q))/(4piepsi_(0)R)`


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