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A charge Q is divided into two charge q and Q-4 The value of q such that the force between them is maximum is |
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Answer» Solution :LET q and `(Q-q)` be the charges on those bodies FORCE between the charges `F= (1)/(4pi in_(0)) ((Q-q)q)/(r^(2))` For F to be MAXIMUM `(dF)/(dq)=0` `(d)/(dq) (Q-q) q= 0 rArr (Q-q) + (-q) = 0` `rArr Q -2q= 0, q= Q//2`. Thus the charge should be divided equally on TEH objects. |
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