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A charge Q is placed at the centre of the line joining two charges q and q. For the system of three charges to be in equilibrium, what should be the value of Q? |
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Answer» Solution :Here Q is in EQUILIBRIUM as it is at the centre and net force on it is zero. For equilibrium of q, net force on it is zero `(1)/(4PI in_(0))(Qq)/((r//2)^(2)) + (1)/(4pi in_(0)) (q^(2))/(r^(2)) = 0` where r is separation between q and q `rArr Q = (-q)/(4)` |
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