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A charge q is placed at the centre of the line joining two equal charges Q. Show that the system of three charges will be in equilibrium ifq= -(Q)/(4) . |
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Answer» SOLUTION :For EQUILIBRIUM of SYSTEM the net force on any charge MUST be zero. Considering net force on A, we have `oversetto (F_(AC) )+oversetto (F_(AB)) =0 ` ` therefore(1)/(4 pi in _0)(Qq)/(((R)/(2))^(2) )+(1)/(4 piin _0) .(Q^(2))/(r^(2)) =0 ` `rArr ""(1)/(4 pi in _0) .(Q)/(r^(2)) [4q +Q]=0` `or"" 4q +Q =0 ` `or "" q= -(Q)/(4) .` 
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