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A charge Q is to be divided into twosmall objects. What should be the value of the charges on the objects so that the force between the objectswill be maximum. |
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Answer» Solution :LET q and (Q-q) be the chargeson those BODIES Force between the charges `F=(1)/(4PI in_(0)) ((Q-q)q)/( r^(2)) rArr q=(Q)/(2)` For F to be maximum `(dF)/(dq)=0` `rArr (Q)/(r^(2)) -(2q)/(r^(2))=0 rArr q=(Q)/(2)` Thuswe have to divide charges EQUALLY on the objects. |
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