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A charged `30muF` capacitor is connected to a 27mH inductor. If the initial charge on the capacitor is 6mC then What is the total energy stored in the circuit initially. What is the total energy at a later time? |
Answer» `E=1/2Q^2/C=1/2((6times10^-3)^2)/(30times10^-6)=0.61` There will be no charge in total energy. |
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