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A charged cork of mass m suspended by a light string is placed in uniform electric field filed of strength E = (hati+hatj) xx 10^(5)NC^(-1) as shown in the figure. If in equilibrium position tension in the string is 2mg//(1+sqrt3) the angle alpha with the vertical can be |
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Answer» `60^@` `E_(X)=E_(y)=10^(5)NC^(-1)` `qE_(x)=T SIN a`, `qE_(y)=mg -T cos a` Dividing `(E_(x))/(E_(y))=(Tsin a)/(mg-T cos a)` or `mg-T cos a=T sin a` or `mg=(2mg)/(1+sqrt(3))(cosa+sin a)` or `OCS a+sin a=(sqrt(3)+1)/(2),rArra=30^(@)` or `60^(@)` 
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