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A charged metallic sphereAis suspendedby a nylon thread. Another chargedis brought close to A such that the distancebetweentheir centers is 10cm as shownin Fig. 1(a).12(a). The resultingrepulsion of Ais noted(for example,byshininga beamof lightand measuringthe deflectionof its shadowon acalibratedscreen). Spheres A and B are touchedby uncharged spheresC and Drespectively, asshownin Fig. 1(a). 12b. C and D are thenremovedand B is broughtcloserto A to a distance of 5.0 cmbetweentheir centers as shown in Fig. 1(a). 12(c). What is the expected repulsionof A on and spheres B and D haveidenteical sizes. Ignorebetweenthier centers. |
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Answer» Solution :Let the origanalrepulsiveforce between A and B be `F = (k q_(1) q_(2))/(r^(2))` As A and C havesame size, their charges are also sharedequally. As charges on A and B are halvedand DISTANCEBETWEEN them is alsohalved from 10 cm to 5 cm, therefore, `F = k((q_(1)//2) (q_(2)//2))/((r//2)^(2)) = (k q_(1) q_(2))/(r^(2)) = F` |
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