1.

A charged oil drop is suspended in uniform field of 3 xx 10^(4) V//m so that it neither falls nor rises. The charge on the drop will be (take the mass of the charge = 9.9 xx 10^(-15)kg "&" g= 10 m//s^(2))

Answer»

`3.3 XX 10^(-18)C`
`3.2 xx 10^(-18)C`
`1.6 xx 10^(-18)C`
`4.8 xx 10^(-18)C`

ANSWER :A


Discussion

No Comment Found

Related InterviewSolutions