1.

A charged particle (change q ) is moving in a circle of radius R with uniform speed v. The associated magnetic moment mu is given by

Answer»

`qvR^(2)`
`qvR^(2)//2`
qvR
`qvR^(2)//2`

SOLUTION :MAGNETIC moment `mu = IA`
Since `T = (2piR)/v`.ALSO, `I=q/T=(qv)/(2piR)`
`therefore mu=((qv)/(2piR))(piR^(2))=(qvR)/2`


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