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A charged particle enters a uniform magnetic field with velocity v_(0) = 4 m//s perpendicular to it, the length of magnetic field is x = ((sqrt(3))/(2)) R, where R is the radius of the circular path of the particle in the field. Find the magnitude of charge in velocity (in m/s) of the particle when it comes out of the field. |
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Answer» `Delta vec(v)=(v_(0)cos 60^(@) hat(i)+v_(0) SIN 60 hat(j)-v_(0)hat(i))IMPLIES |Delta vec(v)|=v_(0)`. 
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