1.

A charged particle is moving with velocity vecv in a uniform magnetic field vecB. The magnetic force acting on it will be maximum when _____ .

Answer»

`vecvandvecB` are in same direction.
`vecvandvecB` are in opposite direction.
`vecvandvecB` are MUTUALLY PERPENDICULAR.
`vecvandvecB` MAKE an angle of `45^(@)` with each other.

Solution :Magnetic force on CHARGED particle,
`vecF=q(vecvxxvecB)`
`thereforeF=qvBsintheta`
Where angle between `vecvandvecB` is `THETA`.
When `vecv_|_vecB`, then `theta=90^(@)`
`thereforeF=qvBsin90^(@)`
`thereforeF=qvB` is maximum force.


Discussion

No Comment Found

Related InterviewSolutions