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A charged particle is projected in a magnetic field of(5 hat I + 9 hat j ) m Tand its acceleration is found to be (9 hat I - x hat j ) xx 10^(-6) m//s^(2). What should be the value of x? |
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Answer» Solution :We know that MAGNETIC force is always perpendicularto the magnetic field. So the acceleration VECTOR must also be PERPENDICULAR to the magnetic field. The dot product of two mutually perpendicular vectors should be zero hence we get the following: `VEC a * vec B = 0rArr(5 hat i + 9 hat j) * (9 hat i - X hat j) xx 10^(-6) xx 10^(-3) = 0 ` ` rArr45 - 9 x = 0 rArrx = 5` |
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