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A charged particle +q of mass m is placed at a distance d from another charge particle -2q of mass 2m in a uniform magnetic field of induction vectro B as shown in the fig.If the particles are projected towards each other with equal speeds v.(Neglect the interaction between the particles) (a)Find the maximum value of the projection speed V_(max) so that the two particles do not collide. b)Find the time interval after which collision occurs between the particles if projection speed equals 2V_(max) (c)In the previous part,assuming that the particles stick after the collision find the radius of the circular path of the particle in subsequent motion.

Answer»


Solution :Final mass `=3m`
Final CHARGE `=-Q`
`R_(f)=(3mV)/(qB)`
By CONSERVATION of linear momentum
`2 mV_(m)sin pi/6+4mV_(m)sin pi/6=3mV_(y)`
`4 mV_(m)cos pi/6-2mV_(m)cos pi/6=3mV_(x)`
`V_(x)=V_(m)/sqrt3`
`V=sqrt(V_(x)^(2)+V_(y)^(2))=(2Vm)/sqrt3, R_(f)=(6mV_(m))/(qBsqrt3)=(2sqrt3_(m))/(qB)xx(qBd)/(2m)=sqrt3 d`


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