1.

A charged particle with velocity barv =xhati+ y hatj moves in a magnetic field barB = y hati+ x hatj . Magnitude of the force acting on the particle is F. The correct option for F is a) No force will act on particle if x = y b) Force will act along y-axis if y < x c) Force is proportional to (x^(2)-y^(2)) if x > y d) Force is proportional to (x^(2) + y^(2)) if y > x

Answer»

a and B are true
a and C are true
b and d are true
c and d are true

Answer :B


Discussion

No Comment Found

Related InterviewSolutions