1.

A charged particle would continue to move with a constant velocity in a region wherein,

Answer»

`vecE=0,vecBne0`
`vecEne0,vecBne0`
`vecEne0,vecB=0`
`vecE=0,vecB=0`

Solution :1. Force on electric charge in electric field is, `vecF_(E)=qvecE` and in magnetic field `vecF_(m)=q(vecvxxvecB)`.
2. If `vecE=0`, then `F_(E)=0andsintheta=0ortheta=0^(@)or180^(@)andBne0` ALTHOUGH `F_(m)=0`.
3. If E = 0 and B = 0, then LORENTZ force `qvecE+q(vecvxxvecB)=0` for this case `vecEne0,vecBne0`.
4. In Lorentz force, `vecF=qvecE+q(vecVxxvecB)`, if F = 0 then `vecE=0andvecB=0`. So option (A, B and D) are TRUE.


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