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A chargeQ is placed at the centreof the line joiningtwocharges q and q. The system of three chargesto be in equilibrium, what should be the value of Q? |
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Answer» Solution :Here Q is in equilibrium as it is at the centre and net force on it is ZERO For equilibrium of q, net force on it must be zero `(1)/(4pi in_(0)) (Qq)/( (R//2)^(2)) +(1)/(4pi in_(0)) (q^(2))/(r^(2))=0` where r is seperation between q and q `rArrQ=(-q)/(4)` |
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