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A chargo q is uniformly distributed on a ring-shaped conductor of radius a. Find the field potential in an arbitrary point on the conductor's axis a distance I away from the plane in which the conductor lies. Using the relation between the potential and the field intensity, find the field intensity at this point. Compare with Problem 4.11. |
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Answer» Solution :To find the potential, DIVIDE the ring into SMALL segments and add up the potentials of these segments. The FIELD strength is `E=-(d varphi)/(dx)=-(q)/(4pi epsi_(0))(d)/(dx) (X^(2)+a^(2))^(-1//2)` `=(1)/(2).(q)/(4pi epsi_(0))(z^(2)+a^(2))^(-1//2)*2x=(qz)/(4pi epsi_(0) sqrt((x^(2)+a^(2))^(3)))` |
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