1.

A chemical reaction was carried out 300 K and 208 K the rate constants were found to be K_(1) and K_(2) respectively. The energy of activation is 1.157xx10^(4) cal "mole"^(-1)and R=1.987 cal. Then

Answer»

`K_(2)=0.25K_(1)`
`K_(2)=0.5K_(1)`
`K_(2)=4K_(1)`
`K_(2)=2K_(1)`

ANSWER :A


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