InterviewSolution
Saved Bookmarks
| 1. |
A chemical reaction was carried out 300 K and 208 K the rate constants were found to be K_(1) and K_(2) respectively. The energy of activation is 1.157xx10^(4) cal "mole"^(-1)and R=1.987 cal. Then |
|
Answer» `K_(2)=0.25K_(1)` |
|