1.

A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be K_(1) and K_(2) respectively. Then

Answer»

`K_(2)=4K_(1)`
`K_(2)=2K_(1)`
`K_(2)=0.25K`
`K_(2)=0.5K_(1)`

SOLUTION :( c ) : For every `10^(@)C` rise in temperature, RATE constant is doubled. Hence, for `20^(@)C` rise in temperature, rate constant will BECOME 4 times, i.e., `K_(1)=4K_(2)" or "K_(2)=0.25K_(1).`


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