1.

A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be k_(1) and k_(2) respectively . Then

Answer»

`k_(2)=4k_(1)`
`k_(2)=2k_(1)`
`k_(2)=0.25 k_(1)`
`k_(2) = 0.5 k_(1)`

Solution :(C ) For every `10^(@)` C RISE in temperature rate CONSTANT becomes double . Therefore for `20^(@)` C rise in temperature rate constant will become 4 times i.e `k_(1)=4 k_(2) "or" k_(2) =0.25k_(1)` .


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