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A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be `k_(1) and k_(2)` respectively. ThenA. `k_(2)=0.25 k_(1)`B. `k_(2)=0.5k_(1)`C. `k_(2)=4k_(1)`D. `k_(2)=2k_(1)`

Answer» Correct Answer - A
By the increase in temperature the activation energy decrease. So the rate of reaction increases. Here temperature difference is 20K. At 10K the rate constant is doubled. Therefore, here it is four times. Hence,
`k_(2)~~0.25k_(1)`


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