InterviewSolution
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InterviewSolution
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The half-life of a reaction is halved as the initial concentration of the reaction is doubled. The order of the reaction isA. 0.5B. 1C. 2D. 0 |
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Answer» Correct Answer - C Relation Between half-life time and initial concentration is `t_(1//2)prop(1)/((a_(0))^(n-1)` Then, `(t_(1//2))_(1)prop(1)/((a_(0))_(1)^(-1))" "...(i)` `(t_(1//2))/(2)prop(1)/((2a_(0))^(n-1)" "...(ii)` Divide by Eq(ii) `(t_(1//2)xx2)/t_(1//2)=((2)^(n-1)(a_(0))^(n-1))/((a_(0))^(n-1))` `2=(2)^(n-1)rArr -1=1` `n=2` |
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