1.

A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 to White precipitate is formed. Bottle 1 +Bottle 3 to White precipitate is formed. Bottle 1 +Bottle 4 to White precipitate is formed. Bottle 2 +Bottle 3 to Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 to No visible reaction is observed. Bottle 3 +Bottle 4 to Blue precipitate is formed. With the help of the above observations answer the following questions. Which of the following bottles will give white precipitate with bottle 1?

Answer»

Bottle 2
Bottle 3
Bottle 4
All of these

Solution :`Pb^(2+)+CO_3^(2-) to PbCO_3 DARR` (WHITE)
`Pb^(2+)+2Cl^(-)toPbCl_2darr`(white)
`Pb^(2+)+SO_4^(2-)toPbSO_4 darr`(white)


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