1.

A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1,2,3 contained colourless solutions,Whilst bottle 4 contained a blue solution. The labels from the bottles were lying scattered ont he floor of the cupboard. They were copper (II) sulphate sodium carbonate lead nitrate hydrochloric acid By mixing sammples of teh contents of the bottles, in pairs, the chemist made the following observations: (i) Bottle 1 + Bottle 2white precipitate (ii) Bottle 1 + bottle 3white precipitate (iii) Bottle 1 + Bottle 4white precipitate (iv) Bottle 2 +Bottle 3colourless gas evolved (v) Bottle 2+ Bottle 4no visible reaction (vi) bottle 3 +bottle 4blue precipitate Q. Chemical formula of white precipitate in observation (i) is:

Answer»

`CuCl_(2)`
`PbCl_(2)`
`PbCO_(3)`
`CuSO_(3)`

SOLUTION :`Pb(NO_(3))_(2)+2HCl to underset("WHITE")(PbCl_(2))darr+2HNO_(3)`


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