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A child has die whose six faces show the letters as given below: The die is thrown once. What is the probability of getting (i) A, (ii) D? |
Answer» Total number of outcomes of a six face die, n(s) = 6 (i) Let `E_(1)`= Event of getting a letter A. `therefore" "n(E_(1)) =2` Probability of getting a letter A `= (n(E_(1)))/(n(S)) = (18)/(90)= (1)/(5)` (ii) Let `E_(2)` = Event of getting a letter D . `therefore" "n(E_(2)) = 1` Probability of getting a letter `D =(n(E_(2)))/(n(S)) = (1)/(6)` |
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