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a chird of a circle of radius 10cms.substends a right angle at the centre.find the area of the corresponding:(use pie=3.14) 1)minor segment 2)major sector |
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Answer» Step-by-step explanation:In the mentioned circle, O is the centre and AO =BO = Radius = 10 cm AB is a CHORD which subtents 90 o at centre O, i.e., ∠AOB=90 o (i) Area of minor segment APB (Shaded region) = Area of Sector AOB - Area of △AOB =( 4 π×10×10 )−(0.5×10×10) =78.5−50 =28.5cm 2 (ii) Area of Major sector = Area of circle - Area of Sector AOB = (π×10×10)−( 4 π×10×10 ) =314−78.5 =235.5cm 2 |
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