✓✓ A circle field of diameter 42 m needs to be cleaned. if the cos

1.	✓✓ A circle field of diameter 42 m needs to be cleaned. if the cost of cleaning the field is Rs. 2.35 per m², find the cost of cleaning the field?
Answer» ${\orange{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}$ Diameter of the circle = 42 m Cost of cleaning per m² = ₹2.35 ${\blue{\bigstar}} \ {\underline{\pink{\textsf{\textbf{To Find :-}}}}}$ Cost of cleaning the whole field ${\red{\bigstar}} \ {\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}$ ${\boxed{\green{\textsf{\textbf{Area of a circle = }}} {\blue{\sf{\pi <klux>R</klux>^2}}}}}$ where, r = RADIUS ${\sf{\pi = \dfrac{22}{7}}}$ ${\orange{\bigstar}} \ {\underline{\blue{\textsf{\textbf{Solution :-}}}}}$ $Radius = {\sf{\dfrac{Diameter}{2}}}$ $\longmapsto {\sf{\dfrac{42}{2}}}$ $\longmapsto {\sf{21 \ m}}$ ${\pink{\textsf{\textbf{Radius = 21 m}}}}$ ACCORDING to the question by USING the formula of Area of a Circle, we get, $\dashrightarrow \ {\green{\sf{Area \ of \ circular \ field = (\pi \times 21^2) \ m^2}}}$ Solving the above equation, $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21^2 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 21 \times 21 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{7} \times 441 \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{ \bigg ( \dfrac{22}{{\cancel{7}}^{ \ 1}} \times {\cancel{441}}^{ \ 63} \bigg ) \ m^2}}$ $: \ \Longrightarrow \ {\sf{(22 \times 63) \ m^2}}$ $: \ \Longrightarrow \ {\sf{1,386 \ m^2}}$ ${\blue{\textsf{\textbf{Area of the circular field = 1,386 sq. m.}}}}$ Cost of cleaning the field = ₹ (1,386 × 2.35) $: \ \Longrightarrow \ {\sf{\purple{Rs. \ 3257.1}}}$ ${\boxed{\orange{\textsf{\textbf{Cost of cleaning the field is Rs. 3257.1}}}}}$