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A circuit containing 80 mH inductor and a 60 muF capacitor in series is connected to a 230 V , 50 Hzsupply has a resistance of 15 Omega. Obtain the average power transferred to each element of the circuit, and the total power absorbed. |
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Answer» SOLUTION :If `R = 15 Omega , " then " I_(rms) = (V_(rms) )/(SQRT(R^2 + (X_L - X_C)^2) ) = (230)/(sqrt( (15)^2 + (53.03 - 25.14)^2)) = 7.26 A` Average power `P_L = P_C = 0` ` P_R = I_(max)^2 R = (7.26)^2 xx 15 = 791 W` TOTAL power consumed = 791 W |
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