InterviewSolution
Saved Bookmarks
| 1. |
A circuit containing a 80 mH inductor and a `60muF` capacitor in series is connected to a 230 V , 50 Hz supply. The resistance of the circuit is negligible. Obtain the current amplitude and rms values. |
|
Answer» `I_(max)=V_(max)/sqrt(R^2+(X_L-X_C)^2)` `X_L=omegaL=100pitimes80times10^-3=25.12Omega` `X_C=1/(omegaC)=1/(100pitimes60times10^-6)=53.03Omega` `thereforeI_(max)=(230sqrt2)/(sqrt((25.12-53.03)^2))=11.6A` `I_(rms)=I_(max)/sqrt2=11.6/sqrt2=8.20A` |
|