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A circuit has a coil of resistance 60 ohm and inductance 3 henry. It is connected in series with a capacitor of `4 mu F` and `A.C` supply voltage of `200 V` and 50 `"cycle"//"sec"`A. the impedance of the coil is `943 Omega`B. the impedance of the coil is `843 Omega`C. the p.d. across the inductor coil is `1110V`D. the p.d. across the capacitor is `924 V` |
Answer» Correct Answer - A,C,D `Z = sqrt(R^(2) + (X_(L) - X_(C ))^(2)) , I_("rms") = (V)/(2)` Impedance of coil `= Z_(1) = sqrt(R^(2) + X_(L)^(2))` Potential drop across the coil `= I_("rms") Z_(1) = I_("rms") sqrt(R^(2) + X_(L)^(2))` Potential drop across capacitor `= V_(c ) = I_("rms") X_(C )` |
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