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A circuit has a resistance of `11 Omega`, an inductive reactance of `25 Omega`, and a capacitive resistance of `18 Omega`. It is connected to an `AC` source of `260 V` and `50 Hz`. The current through the circuit (in amperes) isA. `11`B. `15`C. `18`D. `20` |
Answer» Correct Answer - D `Z=sqrt(R^(2)+(X_(L)-X_(C))^(2))=sqrt((11)^(2)+(25-18)^(2))=13 Omega` Current `i=260/13=20A` |
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