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A circuit has a resistance of 5 ohm connected in series with a capacitance of 10F. Calculate the discharging time constant.(a) 15(b) 50(c) 5(d) 10I have been asked this question in final exam.The doubt is from Growth and Decay topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Correct ANSWER is (b) 50

Best explanation: The discharging TIME constant in a circuit consisting of a CAPACITOR and resistor in series is the product of the resistance and capacitance = 5*10 = 50.



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