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Calculate the energy in the 2F capacitor.(a) 8.6kJ(b) 64kJ(c) 64J(d) 6.4kJThe question was asked at a job interview.Query is from Energy Stored in a Charged Capacitor topic in chapter Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT answer is (d) 6.4kJ

To elaborate: From the EXPRESSION:

WD= CV^2/2 = 2*80^2/2=6400J=6.4kJ.


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