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A circuit is set up by connecting L=100mH, C`=5muF` and R`=100Omega` in series. An alternating emf of 150` sqrt(2)V,(500)/(pi) Hz is applied across this series combination. Which of the following is correct:A. the impedance of the circuit is `141.4 Omega`B. the average power dissipated across resistance `225 W`C. the average power dissipated across inductor is zero.D. the average power dissipated across capacitor is zero |
Answer» Correct Answer - A,B,C,D `Z=sqrt(R^(2)+(omegaL-1/(omegaC))^(2))=sqrt((100)^(2)+(100-200)^(2))=100sqrt(2)` `I_(rms)=V_(rms)/Z` `P_(R)=I_(rms)^(2)R rArr P_(L)=0 rArr P_(C)=0` |
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