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A circular beam of light of diameter (width) falls on a plane surface of glass. The angle of incidence is .I., angle of refraction is .r. and refractive index of glass is mu. Then the diameter of the refracted beam d. is……. |
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Answer» Solution :LET d be the diameter of incident beam and d. be the diameter of refracted beam. Then from figure `COS I = (d)/(PQ), d= PQ cos i` From figure `cos r = (d.)/(PQ)" and "d.= PQ cos r` i.e., `(d.)/(d)= (cos r)/(cos i) implies ("Diameter ofrefracted beam (d.)")/("Diameter of incident beam(d)")= (cos r)/(cos i)`. 
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