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A circular beam of light of diameter (width) falls on a plane surface of glass. The angle of incidence is 'i', angle of refraction is 'r' and refractive index of glass is mu . Then the diameter of the refracted beam d' is |
Answer» SOLUTION : Let d be the DIAMETER of incident beam and d. be the diameter of refracted beam. Then from figure `COS i= (d)/(PQ) , d = PQ cos i ` From figure` cos r = (d.)/(PQ) ` and `d. = PQ cos r ` `i.e., (d.)/(d)= (cos r)/(cos i)` |
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