1.

A circular coil A has a radius R and current flowing through it is I. Another circular coil B has a radius 2R and if 2I is the current flowing throgh it, then the magneitc field at the centre of the circular coil are in the ratio (i.e, B_A to B_B) of

Answer»

`4:1`
`2:1`
`3:1`
`1:1`

Solution :`B_A = (mu_0 I)/(2R) and B_B = (mu_0 (2I))/(2(2R)) = (mu_0 I)/(2R) IMPLIES B_A : B_B = 1 : 1`


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