InterviewSolution
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InterviewSolution
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A circular coil, having 100 turns of wire of radius (nearly) 20 cm each, lies in the X-Y plane with its centre at the origin of coordinates. Find the magnetic field at the point (0, 0, 20sqrt(3)cm), when the coil carries a current of (2/pi) A. |
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Answer» Solution :As per QUESTION the given POINT lies at the AXIAL line of the circular coil at a distance `x = 20sqrt(3)` CM `=0.2 XX sqrt(3)m` from the centre of coil. Moreover, `N = 100, R = 20 cm = 0.2 m and I = (2/pi)A` `:.` Magnetic field `B = (mu_0 NIR^2)/(2[R^2 + x^2]^(3/2)) = ((4 pi xx 10^(-7)) xx 100 xx (2/pi) xx (0.2)^(2))/(2[(0.2)^(2) + (0.2 xx sqrt(3))^(2)]^(3//2)) = 6.3 xx 10^(-5) T` |
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