A circular coil having an area of 3.14 × 10^-2 m^2and 30 turns is rotated about its vertical diameter with an angular speed of 70 rad^-1 in a uniform horizontal magnetic field of magnitude 5 × 10^-2 T. If the coil forms a closed loop of resistance 15 Ω, what is the average power loss due to Joule heating?(a) 0.360(b) 0.362(c) 0.724(d) 0.726I had been asked this question during an interview.Query is from Energy Consideration: A Quantitative Study in section Electromagnetic Induction of Physics – Class 12

A circular coil having an area of 3.14 × 10^-2 m^2and 30 turns is rot

1.	A circular coil having an area of 3.14 × 10^-2 m^2and 30 turns is rotated about its vertical diameter with an angular speed of 70 rad^-1 in a uniform horizontal magnetic field of magnitude 5 × 10^-2 T. If the coil forms a closed loop of resistance 15 Ω, what is the average power loss due to Joule heating?(a) 0.360(b) 0.362(c) 0.724(d) 0.726I had been asked this question during an interview.Query is from Energy Consideration: A Quantitative Study in section Electromagnetic Induction of Physics – Class 12
Answer» Correct answer is (B) 0.362 The best EXPLANATION: Given: N = 30; A = 3.14 × 10^-2 m^2 ; Angular velocity (ω) = 70 rad^-1; B = 5 × 10^-2 T; R = 15 Ω Emf (E) = NABω E = 30 × 3.14 × 10^-2 × 5 × 10^-2× 70 E = 3.297 V Current (I) = \(\frac {E}{R}\) I = \(\frac {3.297}{15}\) I = 0.2198 A Average power loss (P) = \(\frac {I^2 R}{2}\) P = 0.2198^2 × \(\frac {15}{2}\) P = 0.362 W Therefore, the average power loss DUE to Joule heating is 0.362 W.

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