1.

A circular coil having N turns is made from a wire L meter long. If a current of I ampere is passed through this coil suspended in a uniform magnetic field of B tesla, find the maximum torque that can act on this coil.

Answer»

`(BIL^(2))/(2piN)`
zero
`(BIL^(2))/(4piN)`
`(BIL^(2))/(8pi^(2)N)`

Solution :A coil having N TURNS is MADE from the wire having length L m. Radius of this coil = R.
Numbers of turns in `2piR` length = 1
`therefore` Numbers of turns in L length = `L/(2piR)=N`
`thereforeR=L/(2piN)`
Area of cross section of coil A = `piR^(2)`
`thereforeA=(PIL^(2))/(4pi^(2)N^(2))=L^(2)/(4piN^(2))`
Torquc PRODUCED in coil after passing current through it is,
`tau=NIAB=(NIL^(2)B)/(4piN^(2))`
`thereforetau=(IL^(2)B)/(4piN)Nm`


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