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A circular coil of 20 hours and radius 10cm is placed in an uniform magnetic field of 0.17 normal to the plane of the coil if the current in the coil is 5.0A. What is the average force on each electron in the coil due to the magnetic field ? The coil is made of copper wire of cross - (a) sectional area 10^(-5) m ^(+2)and the free clectron density in copper is given to be about 10^(29)//m^(3) . |
| Answer» Solution :(a) ZERO, (b) zero, (c) force on each ELECTRON is `evB = IB//(nA) = 5 ×x 10^(-25)`N. Note: Answer (c) denotes only the MAGNETIC force. | |