1.

A circular coil of 200 mm diameter is made of 100 turns of thin wire and carries a current of 50 mA. Find the magnetic field induction in the centre of the coil and on the coil'axis 100 mm away from its centre.

Answer»


Solution :Neglecting the thickness of the wire as COMPARED with the radius of the coil and the other DIMENSIONS, we obtain an expression `B=(mu_(0)iwa^2)/(2(a^2+H)^(3//2))`
where to is the NUMBER of turns, a is the radius of a burn, and h is the distance from the centre to the point on the axis of the coil where the field is to be determined.


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